EXAM DAA-C01 STUDY SOLUTIONS | PASS4SURE DAA-C01 STUDY MATERIALS

Exam DAA-C01 Study Solutions | Pass4sure DAA-C01 Study Materials

Exam DAA-C01 Study Solutions | Pass4sure DAA-C01 Study Materials

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Snowflake SnowPro Advanced: Data Analyst Certification Exam Sample Questions (Q100-Q105):

NEW QUESTION # 100
You are analyzing website traffic data in Snowflake and notice a sudden drop in page views from a specific country (Country A) starting last month. You have access to the 'WEBSITE TRAFFIC' table with columns: 'date' , 'country', 'page_viewS, 'device_type'. Which of the following queries and techniques would be MOST effective in identifying the potential cause of this anomaly?

  • A. Analyze 'page_viewS by 'device_type' for Country A before and after the drop to see if the drop is concentrated in a specific device type (e.g., mobile, desktop). Use 'CASE statement within the 'GROUP to categorize time periods.
  • B. Run a simple 'SELECT FROM WEBSITE_TRAFFIC WHERE country = 'Country A' AND date DATEADD(month, -3, GROUP BY date ORDER BY date;' to visualize the trend and confirm the drop.
  • C. Execute 'SELECT FROM WEBSITE_TRAFFIC WHERE country = 'Country A' AND date DATEADD(month, -1, CURRENT DATE());' and manually inspect the data for suspicious patterns.
  • D. Join the 'WEBSITE_TRAFFIC' table with a table containing marketing campaign data (MARKETING CAMPAIGNS') on 'date' and 'country' to see if any marketing campaigns were paused or modified in Country A around the time of the drop. Consider using 'LEFT JOIN' to not lose traffic data.
  • E. Use a statistical anomaly detection function (e.g., moving average) on the 'page_views' for Country A and compare against other countries to identify if the drop is specific to Country A. Consider using 'LAG' function with 'OVER' clause to calculate the moving average.

Answer: A,D,E

Explanation:
Options B, C, and D are the most effective. B uses statistical methods to identify the anomaly, C investigates potential external factors (marketing campaigns), and D explores internal segments (device types). Option A is a basic check but doesn't identify causes. Option E is not scalable and inefficient for large datasets. Using a combination of statistical analysis, external data integration, and segmentation provides a comprehensive diagnostic approach.


NEW QUESTION # 101
A financial analyst is using Snowflake to forecast stock prices based on historical data'. They have a table named 'STOCK PRICES with columns 'TRADE DATE (DATE) and 'CLOSING PRICE (NUMBER). They want to implement a custom moving average calculation using window functions to smooth out short-term fluctuations and identify trends. Specifically, they need to calculate a 7-day weighted moving average, where the most recent day has the highest weight and the weights decrease linearly. Which SQL statement correctly implements this weighted moving average calculation?

  • A. Option B
  • B. Option D
  • C. Option C
  • D. Option A
  • E. Option E

Answer: E

Explanation:
Option E is the correct answer because it accurately calculates the 7-day weighted moving average with linearly decreasing weights. It assigns weights from 7 (most recent) down to 1 (oldest) within the 7-day window. The weight calculation '(7 - ROW_NUMBER() OVER (ORDER BY TRADE DATE DESC) + 1)' ensures the most recent date has a weight of 7, and the weights decrease linearly to 1. The sum of the weighted closing prices is then divided by the sum of the weights to get the weighted average. Other options are incorrect because they either calculate a simple moving average, apply incorrect weights, or have syntactic errors. Option B and D's row_number() is ordered ascending, resulting in the oldest data point having the highest weight.


NEW QUESTION # 102
You are working with a table 'ORDERS' containing order data, and a table 'CUSTOMER SEGMENTS containing customer segment information. The 'ORDERS' table has columns 'ORDER ID', 'CUSTOMER ID, and 'ORDER AMOUNT'. The 'CUSTOMER SEGMENTS' table has columns 'CUSTOMER ID', 'SEGMENT ID', and 'SEGMENT NAME'. You need to create a query that enriches the 'ORDERS' table with the customer segment information. However, a customer can belong to multiple segments. You want to include all segments a customer belongs to in the enriched data, resulting in potentially multiple rows per order if the customer is in multiple segments. The output should include 'ORDER ID, 'ORDER AMOUNT, 'SEGMENT ID', and 'SEGMENT NAMES. Which SQL statement would correctly enrich the ORDERS table without losing any order information, even if customers belong to multiple segments?

  • A.
  • B.
  • C.
  • D.
  • E.

Answer: E

Explanation:
An 'INNER JOIN' is the correct choice here. It will return all matching rows between the 'ORDERS' and tables based on the 'CUSTOMER ID. If a customer belongs to multiple segments, each segment will be returned in a separate row associated with the order. "LEFT JOIN' includes rows from the left table even without a match in the right table which is not needed. 'GROUP BY' in the INNER JOIN' will combine multiple segments with 'ORDER_IDS into one row, which is not needed as all segment names are expected. The subquery approach would only return one segment name per order. 'RIGHT JOIN' include all customer segments on the right which is also not needed.


NEW QUESTION # 103
You are tasked with analyzing website clickstream data stored in a Snowflake table called 'clickstream_events'. Each row represents a click event and contains a 'session_id' , and a 'properties' column of type VARIANT that stores key-value pairs related to the event (e.g., '(page': '[product/123', 'element': You need to extract the 'page' and 'element' values from the 'properties' column and identify the most common 'page'-'element' combinations for each 'session_id'. Furthermore you need to limit the results of your data to the top 5 pages element pair. How can this task be accomplished using Snowflake table functions and analytical functions?

  • A. First create a view that flattens the JSON column using LATERAL FLATTEN, then select from this view to perform the group by and ranking operations.
  • B. Use multiple LATERAL FLATTEN calls, one for 'page' and one for 'element', then JOIN the results on and use QUALIFY ROW_NUMBER() OVER (PARTITION BY 'session_id' ORDER BY COUNT( ) DESC) 5.
  • C. Extract 'page' and 'element' using 'properties:page' and 'properties:element' directly in the SELECT statement, then use GROUP BY 'session_id', 'page', 'element' and QUALIFY ROW NUMBER() OVER (PARTITION BY 'session_id' ORDER BY COUNT( ) DESC) 5.
  • D. Use LATERAL FLATTEN to extract the keys and values from the 'properties' column, then use GROUP BY 'session_id', 'key', 'value' and COUNT( ) to find the most frequent combinations.
  • E. Create a UDF to parse the 'properties' VARIANT and return a table with 'page' and 'element columns, then JOIN this UDF's output with the original table and use QUALIFY ROW NUMBER() OVER (PARTITION BY 'session_id' ORDER BY COUNT( ) DESC) 5.

Answer: C

Explanation:
Option C is the most efficient and Snowflake-idiomatic way to achieve this. Directly accessing 'properties:page' and properties:element' is more performant than using LATERAL FLATTEN when you know the specific keys you need. The QUALIFY clause, combined with ROW NUMBER(), efficiently filters the results to the top 5 combinations per session. LATERAL FLATTEN is generally used when you need to iterate over an array within the VARIANT, not when you're extracting specific key-value pairs. UDF introduces extra overhead.


NEW QUESTION # 104
You are tasked with creating a data model for a global e-commerce company in Snowflake. They have data on customers, products, orders, and website events. They need to support complex analytical queries such as 'What are the top 10 products purchased by customers in the US who have visited the website more than 5 times in the last month?' The data volumes are very large, and query performance is critical. Which of the following data modeling techniques and Snowflake features, used in combination, would be MOST effective?

  • A. A wide, denormalized table containing all customer, product, order, and event data, combined with Snowflake's zero-copy cloning for data backups.
  • B. A star schema with fact and dimension tables, combined with materialized views to pre-aggregate data and clustering on dimension keys in the fact table.
  • C. A fully normalized relational model with primary and foreign key constraints, combined with Snowflake's automatic query optimization.
  • D. A data vault model, combined with Snowflake's search optimization service on the hub tables.
  • E. A star schema with fact and dimension tables, combined with clustering the fact table on a composite key of customer ID and product ID.

Answer: B,E

Explanation:
Options B and E are the most effective. A star schema (B and E) is well-suited for analytical workloads. Clustering the fact table on customer and product IDs (B) helps improve query performance when filtering on those dimensions. Materialized views (E) provide pre-aggregated data for common queries, further boosting performance. Normalization (A) can lead to too many joins. Data Vault (C) is complex and may not be necessary. A wide, denormalized table (D) can be difficult to manage and maintain, and zero-copy cloning is for backup, not performance. Clustering on dimension keys in the fact table works best when coupled with a star schema and the keys are frequently used as a filter.


NEW QUESTION # 105
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